Find two numbers such that one of them exceeds The Other by 18 and their sum is 92
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Answered by
0
Let the numbers be x and y
Their difference given, 18
That means, x-y=18
And, their sum is 92
x+y =92
Hence, add the first and second equation
x-y+x+y=18+92
2x= 110
x=55
y= 37
Their difference given, 18
That means, x-y=18
And, their sum is 92
x+y =92
Hence, add the first and second equation
x-y+x+y=18+92
2x= 110
x=55
y= 37
Answered by
3
HEY !!!HERE IS YOUR ANSWER
=>let one of the number be x
=>other number = x+18
=>x+x+18=92
=>2x=74
=>x=74/2
=>x=37
•1st number=x=37
•2nd number=x+18=37+18=55
HOPE IT HELPS...
=>let one of the number be x
=>other number = x+18
=>x+x+18=92
=>2x=74
=>x=74/2
=>x=37
•1st number=x=37
•2nd number=x+18=37+18=55
HOPE IT HELPS...
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