Question

find two numbers such that one of them exceeds the other by 8 and their sum is 80.​

Answer 1

Step-by-step explanation:

$x + x + 8 = 80$

$2x + 8 = 80$

$2x = 80 - 8$

$2x = 72$

$x = 72 \div 2$

$x = 36$

If x = 36 then the other number will exceeds x by 8 , so

$x = 36$

$x + 8 = 36 + 8$

$x = 44$

Therefore , The first number is 36 and the other is 44

PROOF :

$36 + 44 = 80$