Find two numbers such that one of them exceeds the other by 18 and there sum is 92
Answers
Answered by
14
heya mate here is your answer ....
let the first no. be x
and other be x+18
so,
x+x+18=92
2x + 18 =92
2x=92-18
2x=74
x=74÷2
x=37
and other no. is
x+18=37+ 18 =75
hope this helps you...
let the first no. be x
and other be x+18
so,
x+x+18=92
2x + 18 =92
2x=92-18
2x=74
x=74÷2
x=37
and other no. is
x+18=37+ 18 =75
hope this helps you...
Answered by
0
LET THE NUMBERS BE x AND x+18.
x+x+18 = 92
2x+18 = 92
2x = 92-18
2x = 74
x = 37
NUMBERS ARE 37 AND 75.
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