Question

find two numbers such that one of them exceeds the other by 6 and their sum is 18

Answer 1

Let the 1st number x

2nd number be x + 6


A/q,


x + x + 6 = 18

2x + 6 = 18

2x = 18 - 6

2x = 12

x = $\frac{12}{2}$

x = 6


1st number = 6

2nd number => x + 6 => 6 + 6 => 12

Answer 2

Let the no. be x.

other, no. be x + 6

Acoording to the question,

x + x + 6 = 18

2x + 6 =18

2x = 18-6

2x = 12

x = 12 / 2

x = 6

Other number = x + 6

=> 6 + 6

=12

So, the numbers are 6 & 12.