Question

Find two numbers such that one of them exceeds the other by 9 and their sum is 81.

Answer 1

Hi ,

Convert given word problem into algebraic

equation.

Let first number = x

Second number = 9 exceeds the first number

Sum of the two numbers = 81

x + ( x + 9 ) = 81

x + x + 9 = 81

2x = 81 - 9

2x = 72

x = 72 / 2

x = 36

Therefore ,

First number = x = 36,

Second number = x + 9 = 36 + 9 = 45

I hope this helps you.

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Answer 2

Step-by-step explanation:

Let's the numbers to be x

there are 2 numbers

so x+x=2x

2x+9=81

2x= 81-9

2x =72

x=72/2

x=36

one number is 36

another number is 36+9=45

as one number exceeds the other

by 9

verify

45+ 36=81

Hope the helpful to you

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