Math, asked by lucifer2246, 8 months ago

Find two numbers such that one of them exceeds theke other by 13 and their sum is 85​

Answers

Answered by shashicha1980
2

Answer:

49,36

Step-by-step explanation:

let them two numbers be x and y.

then,

x - y = 13. .....1

x + y = 85. ....2

now,

adding equal 1 and 2, we have,

2x = 98

x = 98/2

x = 49.

putting x = 49, in eq.2,we have ,

49 + y = 85

y = 85 - 49

y = 36.

hence, the two numbers are 49 and 36.

Answered by achintamp
1

Answer:

let one number be x

another no.be y

B/P

x=y+13 (1)

now,it is given that their sum is 83

B/P

x+y=85

》y+13+y=85 (from equation 1,x=y+13)

》2y+13=835

》2y=85-13

》2y=72

》y=72/2

》y=36

now substituting this value of y=36 in equation 1 we get

x=13+36

x=49

so x=49,y=36 is the solution

hope it will help you.

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