Question

Find two numbers such that one of them is 5 times the other and their difference is 132

Answer 1

let no's be x and y..
x-y=132;
2nd equation
5y=x
so putting value of y
5y-y=132
4y=132;
y=33;
33×5=x
x=165;
hope answer helps you...
please mark as brainliest...

Answer 2

x=5y since one number is 5 times the other. x-y=132 since the difference between the numbers is 132. now, substitute x=5y in x-y=132, 5y-y=132. 4y=132. y=33. x=5y, x=165.