Question

find two numbers such that one of them is five times the other and their difference is 132

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Answer 1

Answer:

let two numbers be=P and Q

according to question

one number is five times the other

therefore

p = 5Q..............(1)

also their difference is 132

P - Q=132..........(2)

putting the value of equation 1 on equation 2

we get

=≥5Q - Q=132

=≥4Q=132

=≥Q=33..............(3)

hence we get the value of Q is equals to 33

putting the value of Q on equation 1

=≥P=5×33

=≥P=165

hence we get the value of P is equals to 165

so this is your answer I hope that it is helpful for you