find two numbers such that one of them is four times the other and their difference is 21
Answers
Answered by
1
Answer:
First number is=7
Second number is=28
Step-by-step explanation:
4x-x=21
3x=21
x=21/3
x=7
Then First number is 7
Then Second number is 28
Let`s check
4*7-7=21
28-7=21
Answered by
1
Answer:
let one number be x
and another number be 4x
According to given statement
4x-x=21
3x=21
x=7
hence one number be 7
and another number 4x=4×7 =28
Similar questions