Question

Find two numbers such that one of then exceeds the other by 9 and their sum is 81

Answer 1

Answer:

36 and 45

Step-by-step explanation:

Define x:

Let x be one of the number

The other number is (x +9)

Solve x:

Their sum is 81

x + (x + 9) = 81

x + x + 9 = 81

2x + 9 = 81

2x = 72

x = 36

Find the numbers:

one number = x = 36

the other number = x + 9 = 36 + 9 = 45

Answer: The two numbers are 36 and 45

Answer 2

Hey mate!!

Here's your answer

Let the first number = x
Second number = 9 exceeds the first number
= x+9
Sum of the two numbers = 81
x+(x+9)=81
x+x+9=81
2x+9=81
2x=81-9
2x=72
x=72/2
x=36

Therefore,

First number = x
= 36
Second number = x+9
= 36+9
=45

Hope it helped you....Mark me as brainliest.....