find two numbers such that one third of the first number added to one fifth of the second number gives 20 and one sixth of the first added to twefth of the second gives 9
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let x ,y
1/3 x + 1/5y =20
1/6 x +1/12 y =9
so , 5x + 3y =15*20 = 300
and , 2x + y = 12*9 = 108
now , 6x + 3y = 32 4
so , x = 24 = first no.
24 + y = 108
so y = 84 = second no. .....~@lice
1/3 x + 1/5y =20
1/6 x +1/12 y =9
so , 5x + 3y =15*20 = 300
and , 2x + y = 12*9 = 108
now , 6x + 3y = 32 4
so , x = 24 = first no.
24 + y = 108
so y = 84 = second no. .....~@lice
Anonymous:
is it ryt ? if yes then surely mark as brainliest ! :)
i think y is wrong ?
2x + y =108
x=24 , so 48 +y =108
y = 60
now perfect , sorry for calculation mistake !
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