Question

find two numbers such that the larger number added to three times the smaller number gives 7 and twice the larger number added to the smaller number gives 9.

Answer 1

let smaller number be x
and larger number be y
according to the question,
y+ 3x = 7
2y + x = 9
now solve these two equations by every method like, elemination, substitution etc.

Answer 2

let the larger no.be y and smaller no.be x
(y+3x=7)eq.1
(x+2y=9)eq.2
multiply the eq.1 with 2
so,the eq.are
2y+6x=14 eq.3
x+2y=9 eq.4
by changing the signs of eq.4
the eq.are now
2y+6x=14
-x-2y=-9
(subtract the eq.3 from eq.4)
5x=5
x=5/5=1
x=1
putting x=1 in eq.2
1+2y=9
2y=9-1
2y=8
y=8/2
y=4
the answers are
x=1
y=4
this method is done by eliminating the coefficient
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