Question

Find two numbers such that the sum of the thrice the first and the second is 142, and four times the first exceeds the second by 138.

Answer 1

Answer:

40 and 22

Step-by-step explanation:

Let the first number be x and the second number be y. Then, we have: 3x + y = 142 ……….(i) 4x - y = 138 ………(ii) On adding (i) and (ii), we get 7x = 280 ⇒ x = 40 On substituting x = 40 in (i), we get: 3 × 40 + y = 142 ⇒ y = (142 – 120) = 22 ⇒ y = 22 Hence, the first number is 40 and the second number is 22