Question

Find two numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.

Answer 1

Hi...☺

Here is your answer...✌

Let the two numbers be x and y

According to the question,

3x + y = 142 .....(1)

And,

4x-y = 138 .....(2)

By adding eq(1) and eq(2)
We get

3x+y+4x-y = 142+138

7x = 280

x = 280/7

x = 40

Putting x = 40 in eq(1)
We get,

3(40)+y = 142

120+y = 142

y = 142-120

y = 22

HENCE,

The two numbers are 40 and 22

Answer 2

Answer:

Let the two numbers be x and y

By data,

3x+y=142-----(1)

4x-y=138-----(2)

Elimination :

(By Adding equation 1 and 2)

We get

7x=280

X=280/7

X=40

Substitute x in eq 1

3x+y=142

3(40)+y=142

120+y=142

Y=142-120

Y=22

Hence,the first number is 40 and the second number is 22.

Hope it helps u☺☺