Question

Find two numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.

Answer 1

Let us assume, the two numbers are x and y.

Given:

3x + y = 142 ------------1

And also given:

4x – y = 138

y = 4x – 138 --------------2

Substitute the value of y from eqn 2 in eqn 1

3x + 4x – 138 = 142

7x - 138 = 142

7x = 142 + 138

7x = 280

x = 40

Therefore, y = (4 * 40) – 138 = 22

The two numbers are 40 and 22

Answer 2

Answer:

Step-by-step explanation:

Given :-

Sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.

To Find :-

Two numbers

Solution :-

Let the first number be x

And the second number be y.  

According to question

3x + y = 142 ……........….(i)  

4x - y = 138 …….........…(ii)  

On adding (i) and (ii),

⇒ 7x = 280  

⇒ x = 40  

Putting x value in eq (i)

⇒ 3x + y = 142

⇒ 3 × 40 + y = 142  

⇒ y = (142 – 120) = 22  

⇒ y = 22  

Hence, the first number is 40 and the second number is 22.