Question

find two numbers such that the sum of twice of the first and the second is 61 and thrice the first exceeds the second by 29

Answer 1

Answer:

18,25

Step-by-step explanation:

Let the numbers be x and y. Then,

2x+y=61  → (1)                     3x=y+29

                                          3x-y=29 →(2)

Add (1) and (2)

5x=90

 x=18

From (1)

2(18)+y=61

y+36=61

y=25