Question

Find two numbers such that the sum of twice the first and thrice the second is 97 and four times the first exceeds six times the second

Answer 1

Answer:

kya yaar yeh sab kya leke chale aate ho question...

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Answer 2

Answer:

SOLUTiOn

let the first no. and second no. be x and y then,

◆the sum of twice first and thrice the second no. is 97

=>2x+3y=97_

1)

◆four times the first exceeds six time the second by 14

=>4x-14-6y

=>4x-6y=14_

●From i) & ii) we have:

2x+3y=97

4x-6y=14_

we have:

8x+12y=388

8x-12y=28

16x=416

x=416/16

x=104/4

x=26

putting this in eq 1) we have:

3y=97-52

3y=45

y=45/3

y= 15

hope it helps ;)

( HUCKLEBERRY) :)