Question

find two numbers such that the sum of twice the first and thrice the second ois 97 and four times the first exceeds six time the second by 14

Answer 1

»»»» »»»»»(★)««««« ««««
$SoLuTiOn$

>>>>>>>>><<<<<<<<<<

•let the first no. and second no. be x and y then,

◆the sum of twice first and thrice the second no. is 97

=>2x+3y=97________1)

◆four times the first exceeds six time the second by 14

=>4x-14=6y

=>4x-6y=14___________2)

●From i) & ¡¡) we have :

2x+3y=97______(×4){multiplying with 4}
4x-6y=14______(×2){multiplying with 2}

we have:

8x+12y=388

8x-12y=28
___________
16x=416

x=416/16

x=104/4

x=26

putting this in eq 1) we have:

3y=97-52

3y=45

y=45/3

y=15

»»»» »»»»»(★)««««« ««««