Math, asked by Kattriha1900, 9 months ago

Find two numbers such that their mean proportion is 16 and third proportion is 1024.

A) 4 and 32 B) 4 and 64 C) 8 and 64 D) 8 and 32

Answers

Answered by sureshkumardagar22
0

Solution-: 4and16

For number a and b mean proportion=

√(ab)

√(4*16)=8

For number a and b third proportion=(b^2)/a

(16^2)/4

=64

hope it helps you

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