Find two numbers such that their mean proportion is 16 and third proportion is 1024.
A) 4 and 32 B) 4 and 64 C) 8 and 64 D) 8 and 32
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Solution-: 4and16
For number a and b mean proportion=
√(ab)
√(4*16)=8
For number a and b third proportion=(b^2)/a
(16^2)/4
=64
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