find two numbers such that their product is 96 and their difference is -40
Answers
Answered by
1
Answer:
1.57i check out the workings.
Mark me as brainiest. Thanks!
Step-by-step explanation:
xy = 96
x-y = -40
xy = 96
y(x-y = -40y)
xy = 96
xy - y^2 = -40y^2
xy = 96
xy = -40y^2 + y^2
xy = 96
xy = -39y^2
96 = -39y^2 (divide by co-efficient of y^2)
-2.4615384615385 = y^2
y = 1.56892908 i approx. 1.57i (i is an imaginary number in math.)
Similar questions