Question

find two numbers such that their sum 42 and deference is 16​

Answer 1

Answer:

29 and 13

its the ans u can check by adding or subtracging

Answer 2

Answer:

The numbers are :

• 18 & 24

Step-by-step explanation:

Given that,

• Sum of two numbers is 42
• Their difference is 16.

Considering :

The two numbers as "x" and "y"

Thier sum :

• (x + y) = 42.......(i)

Difference :

• (x - y) = 16 ....... (ii)

Subtracting eq. (i) from eq.(ii) :

$(x + y) = 42 \\ { \underline{{(x - y) = \: \: 6}}}$

$: \implies 2x = 36$

$: \implies x = 18$

The value of "x" is 18

Substitute the value of "x" in eq. (i) :

→ x + y = 42

→ 18 + y = 42

→ y = 42 - 18

→ y = 24.

The value of "y" is 24.