Math, asked by mits17, 7 months ago

Find two numbers such that three times the larger is greater than twice the smaller by 10 and the larger added to twice the smaller give 6​

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Answered by gorakchan4
0

Answer:

ANSWER

Let the numbers be x and y

the number at ones place is y

and number on tens place is 10x

so the digit will be 10x+y

The interchange of digit is =10y+x

It is given the difference between the digit and interchange is 63 so

10x+y−(10y+x)=63

9x−9y=63

x−y=7

The difference between the digits is 7.

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