Question

find two numbers suchh that one of them exceeds the otherr by 18 and their sum is 92

Answer 1

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here is ur answer
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Answer 2

$\sf\underline{Step-by-step \: explanation}$

$\sf\underline{Let \: the \: number \: be \: x}$

x+x+18= 92

2x+18= 92

2x= 92-18

2x= 74

x= 74÷2

x= 37

Hence, the numbers are...

x= 37

x+18= 37+18= 55


The first number is,

${\boxed{\boxed{\sf{\blue{37}}}}}$

The second number is,

${\boxed{\boxed{\sf{\red{55}}}}}$

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$\small\sf\red{Thanks!!}$...

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