Question

Find two numbers!!
Their sum is 6 and their difference is 36
WILL MARK BRIANLEST FOR RIGHT ANSWER!!!!!!!!!

Answer 1

$\textsf{Let the numbers = x \& y} \\ \\ \\ \textsf{Sum of the numbers = 6} \\ \\ x+y=6\ \ \ \ \ \ \ \ \ \ \longrightarrow\ \ \ (1) \\ \\ \\ \textsf{Difference of the numbers = 36} \\ \\ x-y=36\ \ \ \ \ \ \ \ \ \ \longrightarrow\ \ \ (2)$

$\textsf{By adding equations\ (1)\ \&\ (2) ,} \\ \\ \begin{tabular}{c}\ \ \ x+y=6 \\ + \ x-y=36 \\ \cline{1-}\ \ \ \ \ \ \ \ 2x = 42 \\ \ \ \ \ \ \ \ \ \ \ x=\bold{21} \end{tabular}$

$\textsf{By subtracting\ (2) \ from\ (1) ,} \\ \\ \begin{tabular}{c}\ \ \ x+y=6 \\-\ \ \ x-y=36 \\ \cline{1-}\ \ \ \ \ \ \ \ \ \ 2y = -30 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ y=\bold{-15} \end{tabular}$

$\textsf{Thus, the numbers are}\ \ \Large \textbf{21}\ \normalsize \textsf{and}\ \Large \ \textbf{-15}\normalsize.$