Question

Find two numbers which differ by 10 and their sum is twice their difference

Answer 1

Step-by-step explanation:

Let one number be x.

Then, other number will be (x-10)

By given conditions, x+(x-10) = {x-(x-10)}^2

2x-10 = 100

2x= 100+10

2x= 110

x= 110/2

x= 55

So, 1st no.= 55

2nd no.= 55-10 = 45

Answer 2

Answer:

good morning and a warm welcome to everyone I know my friend is going to be faced due to difference on measurement units in different countries only points to the use of different scales in different parts of the world and