Question

find two numbers which differ by 9 and are such that four times the larger added to three times the smaller gives 92​

Answer 1

Answer:

Let the larger number be x and smaller number be y; then

x-y=9 [equation 1]

4x+3y=92 [equation 2]

Now take both equations:-

x-y=9

4x+3y=92

Now multiply equation 1 by 4

4x-4y=36

4x+3y=92

-__-___-__

-7y=-56

y=8

x=9+8=17

Therefore, the numbers are 17 and 8

Step-by-step explanation:

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