Math, asked by Indrajith4441, 9 months ago

Find two numbers whose A.M exceeds their G.M by 1/2 and their H.M by 25/26

Answers

Answered by empathictruro
20

Answer:

Let the two numbers be a and b

The A.M of the numbers is given by the formula (a+b)÷2

The G.M of the numbers is given by the formula √a×b

The H.M of the numbers is given by the formula 2÷((1÷a)+(1÷b))

A.M exceeds G.M by 1/2

(a+b)÷2 +(1÷2)= √a×b

(a+b+1) ÷2= √a×b

A.M exceeds H.M by 25/26

(a+b)÷2 +(25÷26) = 2×a×b ÷(a+b)

(13a + 13b +25)÷ 26= 2ab÷(a+b)

We have two equations and have two variables we can solve the equations and we can obtain the value of a and b

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