find two numbers whose difference is 1 and product is 72
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Answered by
16
Step-by-step explanation:
Equation........ =_____=
let x be first number
and y be second
x - y = 1
x= 1+y....(1)
xy = 72
(1+y)y = 72
y +y^2 = 72
y^2 +y -72 = 0
-1 +/-√289/2
-1 + 17/2 or -1-17/2
x= 8 or x = -9
if x = 8 or if x = -9
x - y = 1 or x - y = 1
8 -y = 1 or -9 -y = 1
y = 7 or y = -10
Hope it helps uh!
Answered by
10
Answer:
this answer is correct
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