Question

FIND TWO NUMBERS WHOSE DIFFERENCE IS 3 AND THE SUM OF SQUARES OF THOSE NUMBER =117. WITH PROPER EXPLAINATION

Answer 1

hope this helps you buddy....

Answer 2

Here is your Answer friend
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let the first number be X & second number be Y

According to question

$x - y = 3 \\ x = y + 3 \\ squqre \: of \: the \: number \: sum \\ \\ {x}^{2} + {y}^{2} = 117 \\ putting \: the \: value \: of \: x \\ \\ {(y + 3)}^{2} + {y}^{2} = 117 \\ {y}^{2} + 9 + 6y + {y}^{2} = 117 \\ {2y }^{2} + 6y = 117 - 9 \\ {2y}^{2} + 6y - 108 = 0 \\ {y }^{2} + 3y - 54 = 0 \\ \\ now \: factorise \\ \\ {y}^{2} + 9y - 6y - 54 = 0 \\ y(y + 9) - 6(y + 9) = 0 \\ (y - 6)(y + 9) = 0 \\ y = 6 \: and \: - 9 \\ thus \: - 9 \: negative \: \\ number \: so \: it \: can \: be \: neglect \\ \\ put \: the \: value \: y = 6 \\ x - 6 = 3 \\ x = 3 + 6 \\ x = 9 \: \\ y = 6 \\ \\ hope \: its \: helpful$