Find two numbers whose mean proportional is 16 and the third proportional is 128.
Answers
Answered by
0
Answer:
the two number are 8 and 32
Answered by
6
Answer:
Step-by-step explanation:
Let the number be a and b
∴
√ab = 16
=>ab = 16^2 =256............(i)
Again,
a/b = b/128
=>b^2=128a=128∗256/b ...... ( a=256/b) ......From (i)
=>b^3=128∗256
=>b =32
∴ab=256
=>a=256/b = 256/32 =8
∴a = 8 and b = 32
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