Question

Find two numbers whose mean proportional is 16 and the third proportional is 128.

Answer 1

Answer:

the two number are 8 and 32

Answer 2

Answer:

Step-by-step explanation:

Let the number be a and b

∴

√ab = 16

=>ab = 16^2 =256............(i)

Again,

a/b = b/128

=>b^2=128a=128∗256/b ...... ( a=256/b) ......From (i)

=>b^3=128∗256

=>b =32

∴ab=256

=>a=256/b = 256/32 =8

∴a = 8 and b = 32