Find two numbers whose products is 36 and different is 5
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Let x and y are the numbers. As per question
x-y=5 and xy=36
Now x=5+y if we put the value in xy=36
We get (y+5)y=36
Or y^2+5y=36
Or y^2+5y-36=0 now solving the equation
We get y^2+9y-4y-36=0
Or y(y+9)-4(y+9)=0
Or (y+9)(y-4)=0
Or y=-9 and y=4
Now taking the positive value of y=4 we get
x=9
Hence the answer is 4 and 9.
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