Question

Find two numbers whose sum -3 and product is -108

Answer 1

Answer:

9 and -12

Step-by-step explanation:

Let the two numbers be x and y

Given: x + y = -3 -- (1)

           xy = -108 -- (2)

Now x = -3 - y from equation (1)

Putting this in euation (2)

$(-3 - y)(y) = -108$

$-3y - y^{2} = -108$

$y^2 + 3y - 108 = 0$

$y^2 + 12y - 9y - 108 = 0$

$y(y+12) - 9(y+ 12) = 0$

$(y-9)(y+12) = 0$

Thus if y-9=0

y = 9

x = -3 - 9 = -12

if y+ 12 = 0

y = -12

x = -3 -(-12) = -3 + 12 = 9

Thus 2 numbers are 9 and -12

Answer 2

Answer:

Step-by-step explanation: