Question

find two numbers whose sum and product are respectively 13 and 40​

Answer 1

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Let m and n be the numbers.

Then: m + n = 13 and mn = 40

Then: n = 13 - m

So:m(13 - m) = 4013

m-m² = 40m² - 13m + 40 = 0

(m-8)(m-5) = 40m = 8 or 5

Thus, the two numbers are 8 and 5.