Find two numbers whose sum is -15 but their product is 36.show both problems for credit
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Assume numbers as x and y
As per ques
Eqn 1. X+Y = -15
Eqn 2. XY= 36
Take everything to the rhs except Y in eqn 2 u get
Y= 36/x
Substitute the value in eqn 2
U get X+ 36/x = -15
Solve this eqn
U get x^2 + 36=-15x
Or x^2 + 15x+36= 0
Solve this quadratic
X^2 +3x +12x+36=0
X (x+3) +12(x+3)
(X+12)(x+3) = 0!
So x =-12
And x =-3
As per ques
Eqn 1. X+Y = -15
Eqn 2. XY= 36
Take everything to the rhs except Y in eqn 2 u get
Y= 36/x
Substitute the value in eqn 2
U get X+ 36/x = -15
Solve this eqn
U get x^2 + 36=-15x
Or x^2 + 15x+36= 0
Solve this quadratic
X^2 +3x +12x+36=0
X (x+3) +12(x+3)
(X+12)(x+3) = 0!
So x =-12
And x =-3
Answered by
0
Answer:
X+Y=-15 -(i)
XY=36-(ii)
replace the value of X from 1 equation
Y=-15-X
put the value of Y in 2 equation
X(-15-X)=36
-15X-Xsquare=36
-Xsquare-15X-36=0
-(Xsquare+15X+36)=0
Xsquare+12X+3X+36=0
X(X+12)+3(X+12)=0
(X+3)(X+12)=0
X=3
X=12
hence the two numbers is 12 and 3
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