Find two numbers whose sum is 16 and sum of whose cube
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Answer:
answer hai eight
ok
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We have to maximise x³+y³ and we have x+y=16
Put x = 16 − y in x³+y³
we get f(y) = 48y²−768y+4096
First derivative is given by
f(y) = 96y−768
Putting this to zero we get, y=8
f(y)=96
Given that second derivative is positive
So given function will have minima when y=8
So x=16−8=8
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