Find two numbers whose sum is 18 and sum of their square is 290
Answers
Answered by
16
x + y = 18
let x be 18-y
so,
(18-y)² + y² = 290
18²+ y² - 36y + y² = 290
2y² - 36y = -34
2y² - 36y +34 = 0
solving the equation
y² -34y-2y+68 = 0
y(y-34) -2( y-34) = 0
(y-2) (y-34) = 0
so,
y= 2 or 34
case 1,
y =2 and x = 16
case 2
y = 34
x = -16
let x be 18-y
so,
(18-y)² + y² = 290
18²+ y² - 36y + y² = 290
2y² - 36y = -34
2y² - 36y +34 = 0
solving the equation
y² -34y-2y+68 = 0
y(y-34) -2( y-34) = 0
(y-2) (y-34) = 0
so,
y= 2 or 34
case 1,
y =2 and x = 16
case 2
y = 34
x = -16
Answered by
3
Answer:
above answer is wrong
Step-by-step explanation:
but I also don't know the answer
Similar questions