Question

Find two numbers whose sum is 19,such that one shall exceed twice the other by 1

Answer 1

Answer:

hello!!

the two numbers are :

9 and 10.

Step-by-step explanation:

let no. be a,b

then, acc. to question  ,

a=b+1

 a+b=19

 b+1+b=19

2b+1=19

2b=19-1

2b=18

b=18/2

b=9

a=b+1

a=9+1

a=10

HOPE IT HELPS....

Answer 2

Let the two numbers be x and y

Sum of two numbers = 19

x + y = 19

y = 19 - x --(1)

Given : One will exceed the other by 1

That means one of the number is 1 more than the other. And also difference between the numbers is 1

Difference of the given numbers = 1

x - y = 1

x - (19 - x) = 1

x -19 + x = 1

2x - 19 = 1

2x = 1 + 19

2x = 20

x = 20/2

x = 10

Substitute the value of x in (1) to get the value of y

y = 19 - 10

y = 9

Another method

x + y = 19 --(1)

x - y = 1 ---(2)

Adding (1) & (2)

x + y = 19

x - y = 1

_______________

2x - 0 = 20

________________

2x = 20

x = 20/2

x = 10

Substitute the value of x in (1) to get the value of y

y = 19 - 10

y = 9