find two numbers whose sum is 24 and difference is 8.
Answers
Answered by
2
Let numbers be x and y
x + y = 24
x - y = 8
Solving we get
x = 16
y = 8
x + y = 24
x - y = 8
Solving we get
x = 16
y = 8
Answered by
1
Let the two numbers are x and y
Given
x+y=24----(1)
x-y=8----(2)
Add (1) and (2)
2x=32
x=32/2
x=16
Put x=16 in (1)
16+y=24
y=24-16=8
Therefore
Required two numbers are
x=16, y=8
Given
x+y=24----(1)
x-y=8----(2)
Add (1) and (2)
2x=32
x=32/2
x=16
Put x=16 in (1)
16+y=24
y=24-16=8
Therefore
Required two numbers are
x=16, y=8
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