Question

find two numbers whose sum is 24 and difference is 8

Answer 1

Let the two no.s be x and y
x+y = 24
x-y = 8
On adding the above equation
2x = 32
x = 16
Putting the value infirst equation
y = 8

Answer 2

x+
$x + y = 24 \\ x - y = 8 \\ 2x = 16 \\ x = 8 \\ y = 24 - 8 = 16$