find two numbers whose sum is 26 and the difference is 8
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Answered by
3
let the no.be x and y
according to question,
x+y=26
x-y=8
y got cancelled and 2x=34
x=34/2
x=17
then,y=17-8=9.
hence,x=17
and y=9...
according to question,
x+y=26
x-y=8
y got cancelled and 2x=34
x=34/2
x=17
then,y=17-8=9.
hence,x=17
and y=9...
rudraraj72:
ok...
Answered by
4
let the larger no. be x and smaller no. be y
so, according to the question
x+y= 26 eq. i
and x- y= 8 eq.ii
on adding eq. i and ii we get
x+y=26
x-y=8
----------
2x=34
x=34/2=17
now putting the value of x in eq. i
17 + y=26
y= 26- 17
y =9
so, according to the question
x+y= 26 eq. i
and x- y= 8 eq.ii
on adding eq. i and ii we get
x+y=26
x-y=8
----------
2x=34
x=34/2=17
now putting the value of x in eq. i
17 + y=26
y= 26- 17
y =9
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