find two numbers whose sum is 27 and product is 182
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Step-by-step explanation:
let the two numbers be x,y
x + y = 27
x = 27 - y -------------(1)
xy = 182
x = 182/y ----------------(2)
in both equations LHS is equal so RHS can be equated
27 - y = 182 / y
27y - y^2 = 182
0 = y^2 - 27y + 182
0 = y^2 -13y -14y +182
grouping the terms ,
0 = ( y^2 - 13y ) - 14y + 182
taking y common in 1st group , and 14 in 2nd group
0 = y ( y - 13) - 14( y - 13)
here (y - 13) is common
0 = ( y - 13) (y - 14)
y = 13 { or } 14
if y = 13 , if y = 14 ,
x = 27 - 13 x = 27 - 14
x = 14 { or } x = 13
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Answer:
follow the upper answer it's correct
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