Question

find two numbers whose sum is 27 and product is 182​

Answer 1

Answer:

Let the first number be x and the second number is 27 - x.

Therefore, their product = x (27 - x)

It is given that the product of these numbers is 182.

Therefore, x(27 - x) = 182

⇒ x2 – 27x + 182 = 0

⇒ x2 – 13x - 14x + 182 = 0

⇒ x(x - 13) -14(x - 13) = 0

⇒ (x - 13)(x -14) = 0

Either x = -13 = 0 or x - 14 = 0

⇒ x = 13 or x = 14

If first number = 13, then

Other number = 27 - 13 = 14

If first number = 14, then

Other number = 27 - 14 = 13

Therefore, the numbers are 13 and 14.

Answer 2

Here is ur answer mate:-

let one of the number be 'x'

So, obviously the other one be '27-x' as per the question.

Also, there product is 182

So, we got a equation to form, i.e

(x) × (27-x) = 182

x(27 - x) = 182

⇒ 27x - x² = 182

⇒ x² - 27x + 182 = 0

⇒ x² - 27x + 182 = 0

• factorising it, we get,

⇒ x² - 13x - 14x + 182 = 0

⇒ x(x - 13) - 14(x - 13) = 0

⇒ (x - 13) (x - 14) = 0

⇒ x - 13 = 0 or x - 14 = 0

⇒ x = 13 or x = 14

Hence, the required two numbers are 13 and 14

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