find two numbers whose sum is 27 and product is 182.
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Answered by
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X × 27-x=182
27x-x^2=182
X^2-27x-182=0
X^2-14x-13x-182=0
X (x-14)-13 (x-14)=0
(X-13)(x-14)=0
X=13,14
The numbers are 13 and 14.
Mark brainliest.
27x-x^2=182
X^2-27x-182=0
X^2-14x-13x-182=0
X (x-14)-13 (x-14)=0
(X-13)(x-14)=0
X=13,14
The numbers are 13 and 14.
Mark brainliest.
Answered by
0
Heya ☺
Let the two numbers be x and y
Then
x+y = 27
x = 27-y
and xy = 182
Substituting the value of x
(27-y)y =182
27y - y^2 = 182
y^2 -27y+182= 0
y^2 -14y- 13y +182= 0
y(y -14) - 13( y-14) =0
(y-13) (y-14) =0
y =13
y=14
Then x = 27-13 = 14
x =27 -14 =13
✌✌ Hope it helps u!
Let the two numbers be x and y
Then
x+y = 27
x = 27-y
and xy = 182
Substituting the value of x
(27-y)y =182
27y - y^2 = 182
y^2 -27y+182= 0
y^2 -14y- 13y +182= 0
y(y -14) - 13( y-14) =0
(y-13) (y-14) =0
y =13
y=14
Then x = 27-13 = 14
x =27 -14 =13
✌✌ Hope it helps u!
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