Question

Find two numbers whose sum is 27 and product is 182.

Answer 1

hello mate!.....


given!.....


one num is "x"

second num is "27-x"

from qs ......


x(27-x) = 182

$27x - x {}^{2} = 182 \\ \\ x {}^{2} - 27x + 182 = 0 \\ \\ x {}^{2} - 13x - 14x + 182 = 0 \\ \\ x(x - 13) - 14(x - 13) = 0 \\ \\ (x - 13)(x - 14) = 0 \\ \\ x = 13 \: and \:14 \\ \\ 13 + 14 = 27 \\ \\ 13 \times 14 = 182$


hope it helps u

Answer 2

Hey there!

Q. Find two numbers whose sum is 27 and product is 182.

Answer : Let the required number be x and 27 - x. Then,

⇒ x(27 - x) = 182

⇒ $27x -x^{2} = 182$

⇒ $x^{2} - 27x + 182 = 0$

⇒ $x^{2} - 13x - 14x + 182 = 0$

⇒ x(x - 13) - 14(x - 13) = 0

⇒ (x - 13)(x - 14) = 0

⇒ x - 13 = 0 or x - 14 = 0

⇒ x = 13 or x = 14

Hence, the two numbers are 13 and 14.

Method to check :

⇒ Sum - 13 + 14 = 27

⇒ Product - 13 × 14 = 182