Find two numbers whose sum is 27 and product is 182
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Answered by
3
hi.......
here is your answer.
Let the two numbers be x &y
x+y=27 .... (I)
xy=182
(x+y) ²=x²+2xy+y²
27²=x²+y²+2×182
729=x²+y²+364
x²+y²=729-364
x²+y²=365
(x-y) ²=x²+y²-2xy
(x-y) ²=365-364
(x-y) ²=1
x-y=1 .... (II)
adding (I) &(II)
2x=28
x=14
y=13
hope it helps
please mark it as the brainliest
Answered by
6
SOLUTION___(・∀・)
Let the first no. be x
Second no. be 27-x
Now, x(27-x)=182
= 27x-x^2= 182
A/q__
=x^2-27x+182= 0
=x^2-(13x-14x)+182=0 {let use middle splits term}
=x(x-13)-14(x-13)=0
= (x-13) (x-14)=0
= x= 13 or x= 14 {required no.} ans.
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Anonymous:
hii
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