Question

Find two numbers whose sum is 32 and product is 252.
(a) 18 & 14
(b) 16 & 16
(c) 12 & 20
(d) 8 & 24​

Answer 1

Answer:

let the 2 numbers be a,b

=> a+b = 32 => a = 32-b

=> ab = 252

=> (32-b)b = 252

=> -b²+32b = 252

=> b²-32b+252 = 0

=> b = [-(-32) ± √(32²- 4×252)]/2

= [32 ± √16]/2

= (32 + 4)/2 [or] (32 - 4)/2

= 18 (or) 14

=> a = 14 (or) 18

so, those numbers are 14 and 18

Answer 2

Answer:

Step-by-step explanation:

et the 2 numbers be a,b

=> a+b = 32 => a = 32-b

=> ab = 252

=> (32-b)b = 252

=> -b²+32b = 252

=> b²-32b+252 = 0

=> b = [-(-32) ± √(32²- 4×252)]/2

= [32 ± √16]/2

= (32 + 4)/2 [or] (32 - 4)/2

= 18 (or) 14

=> a = 14 (or) 18

so, those numbers are 14 and 18