Question

find two numbers whose sum is 35 and product is 216​

Answer 1

Answer:

the two numbers are 27 and 8

Answer 2

Answer:

        The numbers are 27 and 8.

Explanation:

• Let the two numbers be 'a' and 'b'.

• Then, as per the question; a + b = 35 and a × b = 216

• Now, we can rewrite the equation a + b = 35, as a = 35 - b ........ (i)

• Now, substituting (i) in equation a × b = 216

We get, (35 - b) × b = 216

⇒ 35b - $b^{2}$ = 216

⇒ $b^{2}$ - 35b + 216 = 0

• On factorization we get,

       $b^{2}$ - 27b - 8b + 216 = 0

⇒ b (b - 27) - 8 (b - 27) = 0

⇒ (b - 27) (b - 8) = 0

⇒ (b - 27) = 0 or (b - 8) = 0

Therefore, b = 27, b = 8

• To conform the solved values; Now, since there are two numbers, there are two cases for two numbers whose sum is 35 and product is 216​.

On using, b = 27

we get, a + 27 = 35

∴ a = 8

And, on using, b = 8

we get, a + 8 = 35

∴ a = 27

• Thus, the two numbers are 27 and 8.

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https://brainly.in/question/2391217

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