find two numbers whose sum is 36 and whose difference is 10
Answers
Answered by
34
Answer:
Let the number be x and y.
As given,
x + y = 36 ---(i)
x - y = 10 ---(ii)
Adding eq(i) and eq(ii) we get,
2x = 46
x = 23
Now putting the value of x in eq(ii)
23 - y = 10
y = 13
So the two numbers are 23 and 13.
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Answered by
11
Answer
= 23 & 13 ( pairs).
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Step by step explanation:-
x + y = 36
x - y = 10
•Add These Two Equation.
2x = 46
x = 23
• Subtract x = 23 into either equation, I like the first.
23 + y = 36
y = 13.
23 and 13 are in the pair.
HOPE IT WILL HELP U.
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