find two numbers whose sum is 45 and difference is 17
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Step-by-step explanation:
The sum of two numbers is 45 and their difference is 17. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 45. In other words, x plus y equals 45 and can be written as equation A:
x + y = 45
The difference between x and y is 17. In other words, x minus y equals 17 and can be written as equation B:
x - y = 17
Now solve equation B for x to get the revised equation B:
x - y = 17
x = 17 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 45
17 + y + y = 45
17 + 2y = 45
2y = 28
y = 14
Now we know y is 14. Which means that we can substitute y for 14 in equation A and solve for x:
x + y = 45
x + 14 = 45
X = 31
Summary: The sum of two numbers is 45 and their difference is 17. What are the two numbers? Answer: 31 and 14 as proven here:
Sum: 31 + 14 = 45
Difference: 31 - 14 = 17..
Hope its help..
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