Math, asked by dulekashish, 19 days ago

find two numbers whose sum is 58 and their difference is 4.​

Answers

Answered by pritybanerjee709
6

Step-by-step explanation:

Let the two numbers be x and y,then according to the question,

x+y=58 and x−y=4

Adding the above two equations

x+y+x−y=58+4

2x=62

x=31

Putting the value of x in any of the equations

31+y=58

y=58-31=27

Therefore the numbers are 5 and 27

Hope it's helps you.

Answered by saniadcunha10
3

Step-by-step explanation:

Let the two numbers be x and y,

then according to the question,

it is given that the sum of the numbers is 58

so,

x+y=58 . .......(1)

and the difference of the two numbers is 4

x-y=4 ........(2)

Adding the above two equations

x+y=58

x-y=4

we get 2x= 62

=62/2

x = 31

put x= 31 in eq (2)

x-y=4

(31)-y=4

-y= 4-31

-y = -27

y = 27

31 and 27 are the two numbers

31+27 =58

31-27=4

hence proved

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