find two numbers whose sum is 58 and their difference is 4.
Answers
Answered by
6
Step-by-step explanation:
Let the two numbers be x and y,then according to the question,
x+y=58 and x−y=4
Adding the above two equations
x+y+x−y=58+4
2x=62
x=31
Putting the value of x in any of the equations
31+y=58
y=58-31=27
Therefore the numbers are 5 and 27
Hope it's helps you.
Answered by
3
Step-by-step explanation:
Let the two numbers be x and y,
then according to the question,
it is given that the sum of the numbers is 58
so,
x+y=58 . .......(1)
and the difference of the two numbers is 4
x-y=4 ........(2)
Adding the above two equations
x+y=58
x-y=4
we get 2x= 62
=62/2
x = 31
put x= 31 in eq (2)
x-y=4
(31)-y=4
-y= 4-31
-y = -27
y = 27
31 and 27 are the two numbers
31+27 =58
31-27=4
hence proved
Similar questions